According to a very large poll in 2015, about 90% of homes in California had...

Raul Walker

Raul Walker

Answered

2022-07-09

According to a very large poll in 2015, about 90% of homes in California had access to the internet. Market researchers wonder if that proportion is now higher, so they take a random sample of 200 homes in California and find that 196 have access to the internet. They want to use this sample data to test H0:p = 0.9 versus Ha:p > 0.9, where p is the proportion of California homes with internet access. Which conditions for performing this type of significance test have been met?
Choose all answers that apply.
I. The data is a random sample from the population of interest.
II. np ≥ 10 and n (1 - p) ≥ 10
III. Individual observations can be considered independent.

Answer & Explanation

Asdrubali2r

Asdrubali2r

Expert

2022-07-10Added 14 answers

All three condition conditions will apply
Cheking for (II) condition. That is
n p 10  and  n ( 1 p ) 10 Given  p = 0.90 n = 200 n p = 200 ( 0.90 ) 180 > 10 n ( 1 p ) = 200 ( 1 0.90 ) = 200 ( 0.10 ) = 20 > 10
When data has random sampling, (I) and (III) condition will automatically met.

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