brunocazelles4dvb

2022-03-31

I have some problems, help

In chi-square tests, the conventional and conservative rule is to require that the difference between the observed and expected frequency for each cell be at least 5.

1. True

2. False

In chi-square tests, the conventional and conservative rule is to require that the difference between the observed and expected frequency for each cell be at least 5.

1. True

2. False

ostijum8dd

Beginner2022-04-01Added 7 answers

Introduction:

The chi-square test is a non-parametric test, commonly used to test whether two categorical variables are associated (chi-square test of independence), whether the distributions of two variables across several categories of a categorical variables are identical (chi-square test of homogeneity), whether a given data set fits a certain pre-defined distribution (chi-square test of goodness of fit), etc.

Explanation:

The chi-square test is suitable to use, provided all the expected frequencies, under the assumption that the null hypothesis is true, are greater than 5.

It must be remembered that the validity of the test does not depend upon the magnitude of the difference between the observed and expected frequencies for each cell, but rather, only on the expected cell frequency.

Hence, the given statement is false.

The chi-square test is a non-parametric test, commonly used to test whether two categorical variables are associated (chi-square test of independence), whether the distributions of two variables across several categories of a categorical variables are identical (chi-square test of homogeneity), whether a given data set fits a certain pre-defined distribution (chi-square test of goodness of fit), etc.

Explanation:

The chi-square test is suitable to use, provided all the expected frequencies, under the assumption that the null hypothesis is true, are greater than 5.

It must be remembered that the validity of the test does not depend upon the magnitude of the difference between the observed and expected frequencies for each cell, but rather, only on the expected cell frequency.

Hence, the given statement is false.

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