What are the mean and standard deviation of a binomial probability distribution with n=17 and...

zakinutuzi

zakinutuzi

Answered

2022-01-16

What are the mean and standard deviation of a binomial probability distribution with n=17 and p=1832?

Answer & Explanation

Kirsten Davis

Kirsten Davis

Expert

2022-01-16Added 27 answers

Explanation:
Unless you have to calculate everything each time, we could simply use known formulas.
In binomial distribution the mean is given by np and variance by np(1-p).
Since in our case n=17 and p=1832=916 the mean is
17916=15316=9.5 and variance is 17916(1916)=1071256. Standard deviation is the square root of variance so we have 1071256=3119162.0454.
ramirezhereva

ramirezhereva

Expert

2022-01-17Added 28 answers

Solution:
The mean of the binomial distribution is interpreted as the mean number of successes for the distribution. To find the mean, use the formula
μ=np
where n is the number of trials and p is the probability of success on a single trial. Substituting values for this problem, we have
μ=171832
Multiplying the expression we have
μ=9.52
The standard deviation of the binomial distribution is interpreted as the standard deviation of the number of successes for the distribution. To find the standard deviation, use the formula
σ=np(1p)
where n is the number of trials and p is the probability of success on a single trial. Substituting values fo this problem, we have
σ=171832(11832)
Evaluating the expression on the right, we have
σ=4.1888
σ=2.0454

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?