John Stewart

2022-01-16

What are the mean and standard deviation of a binomial probability distribution with n=12 and $p=\frac{5}{37}$?

Jeffery Autrey

Expert

Explanation:
Mean = n*p
$SD={\left(n\cdot p\cdot q\right)}^{\frac{1}{2}}$
q=1-p
$Mean=12\cdot \frac{5}{37}=\frac{60}{37}=1.62$

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