Kathy Williams

2022-01-19

What are the mean and standard deviation of a binomial probability distribution with n=11 and $p=\frac{19}{23}$?

zurilomk4

Explanation:
Given -
n=11
$p=\frac{19}{23}$
Mean = np $=11×\frac{19}{23}=9\frac{2}{23}$
$q=1-p=1-\frac{19}{23}=\frac{4}{23}$
$SD=\sqrt{npq}=\sqrt{11×\frac{19}{23}×\frac{4}{23}}=\sqrt{1.58}=1.26$

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