What are the mean and standard deviation of a binomial probability distribution with n=777 and...

Sapewa

Sapewa

Answered

2022-01-18

What are the mean and standard deviation of a binomial probability distribution with n=777 and p=1921?

Answer & Explanation

otoplilp1

otoplilp1

Expert

2022-01-18Added 41 answers

Explanation:
Mean=np=7771921=703
Variance=np(1p)=7771921221=66.9
Standard Deviation=variance=8.18
boronganfh

boronganfh

Expert

2022-01-19Added 33 answers

19210.9
μ=np
=777*0.9
=699.3
σ2=np(1p)
=777*0.9(1-0.9)
=69.93
σ=σ2=69.93=8.18

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