Osvaldo Apodaca

Answered

2022-01-18

Products from a certain machine are too large 15% of the time. What is the probability that in a run of 20 parts, 5 are too large?

Answer & Explanation

Edward Patten

Expert

2022-01-18Added 38 answers

Explanation:

The probability that 5 parts are too large is

and since 5 parts are too large, the other 15 are of acceptable size with probability

ways to do this, so the probability that exactly 5 parts are too large is

redhotdevil13l3

Expert

2022-01-19Added 30 answers

Given, product from a certain machine too large

is 15% of time i.e p=0.15

$\therefore$ q=1-p=1-0.15=0.85

sample size (n)=20

Binomial distribution:$P(X=\gamma )={n}_{{C}_{\gamma}}{p}^{\gamma}{q}^{n-\gamma}$

$\therefore p(X=5)={20}_{{C}_{5}}{\left(0.15\right)}^{5}{\left(0.85\right)}^{15}=0.1028$

Answer = 0.1028

is 15% of time i.e p=0.15

sample size (n)=20

Binomial distribution:

Answer = 0.1028

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