Solve and give the correct answer with using second derivative of the function as follows...

The given function is ${\displaystyle f\left(x\right)is{(x+9)}^2.}$
Obtain the first and second derivative of the function as follows.
${\displaystyle f\left(x\right)={(x+9)}^2}$
${\displaystyle f^{\prime }\left(x\right)=2(x+9)}$
${\displaystyle f^{\prime }\left(x\right)=2}$
Find the critical points as follows
${\displaystyle f^{\prime }\left(x\right)=0}$
${\displaystyle 2(x+9)=0}$
${\displaystyle \frac{2(x+9)}{2}=\frac{0}{2}}$
${\displaystyle x=-9}$
Thus, the function has critical point at ${\displaystyle x=-9}$
Since the second derivative is a constant function and is greater than zero for all values of x, the function has only local minima.
Thus, the function has local minima or minimum at ${\displaystyle (–9,0).}$