UkusakazaL

2021-08-08

Based on a simple random sample of 1300 college students, it is found that 299 students own a car. We wish to construct a $90\mathrm{%}$ confidence interval to estimate the proportions ? of all college students who own a car.
A) Read carefully the text and provide each of the following:
The sample size $?=$
from the sample, the number of college students who own a car is $?=$
the confidence level is $CL=$ $\mathrm{%}$.
B) Find the sample proportion $\stackrel{^}{?}=$
and $\stackrel{^}{?}=1-\stackrel{^}{?}=$

Step 1
(A)
The sample size is, $n=1300$
The number of college students who own a car is,
$x=299$
The confidence level is, $CL=90\mathrm{%}$
Step 2
(B)
The value of sample proportion is,
$\stackrel{^}{p}=\frac{x}{n}$
$=\frac{299}{1300}$
$=0.23$
The value of $\stackrel{^}{1}$ is,
$\stackrel{^}{q}=1-\stackrel{^}{p}$
$=1-0.23$
$=0.77$

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