# sec2(x)−1=0

generals336

## Answered question

2021-05-04

${\mathrm{sec}}^{2}\left(x\right)-1=0$

### Answer & Explanation

${\mathrm{sec}}^{2}\left(x\right)-1=0$

Let: $\mathrm{sec}\left(x\right)=i$

${u}^{2}-1=0$

${u}^{2}-1+1=0+1$

${u}^{2}=1$

$u=\sqrt{1},u=-\sqrt{1}$

u=1, u=-1

Substitute back $u=\mathrm{sec}\left(x\right)$

$\mathrm{sec}\left(x\right)=1,\mathrm{sec}\left(x\right)=-1$

ппп$x=2\u043fn,x=\u043f+2\u043fn$

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