Let F(x) be the unique function that satisfies F(0)=0 and F'(x)=sin(x^3)/x for all x. Find the Taylor series for F(x) about x=0. Wouldn't the value of every derivative at 0 just be 0 ? So how does a Taylor series even exist? If F(0)=0, then can the Taylor series of F(x) be the same as that of F′(x) ?

Aliyah Thompson

Aliyah Thompson

Answered question

2022-11-11

Let   F ( x )   be the unique function that satisfies   F ( 0 ) = 0   and   F ( x ) = sin ( x 3 ) x   for all   x. Find the Taylor series for   F ( x )   about   x = 0.
Wouldn't the value of every derivative at   0   just be   0   ? So how does a Taylor series even exist?
If   F ( 0 ) = 0, then can the Taylor series of   F ( x )   be the same as that of   F ( x )   ?

Answer & Explanation

Eynardfb0

Eynardfb0

Beginner2022-11-12Added 19 answers

You have
F ( x ) = sin ( x 3 ) x
Now use the Taylor series
sin ( t ) = n = 0 ( 1 ) n ( 2 n + 1 ) ! t 2 n + 1
Make t = x 3 to get
F ( x ) = n = 0 ( 1 ) n ( 2 n + 1 ) ! x 6 n + 2
and integrate to get
F ( x ) = n = 0 ( 1 ) n ( 6 n + 3 ) ( 2 n + 1 ) ! x 6 n + 3 + C

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