Evaluate the Sum sum_(i=0)^infty i^N/4^i

pighead73283r

pighead73283r

Answered question

2022-11-09

Evaluate the Sum i = 0 i N 4 i

Answer & Explanation

x0xkatiex0xz6u

x0xkatiex0xz6u

Beginner2022-11-10Added 11 answers

Note that for |x|<1, we have
i = 0 x i = 1 1 x
We then have
i = 0 i x i = x d d x ( i = 0 x i ) = x d d x ( 1 1 x )
If we denote the operator x d d x as L, we then have
i = 0 i x i = L ( 1 1 x )
i = 0 i 2 x i = L ( L ( 1 1 x ) ) = L 2 ( 1 1 x )
And in general,
i = 0 i N x i = L N ( 1 1 x )
Hence,
i = 0 i N 4 i = L N ( 1 1 x ) | x = 1 / 4
Also, this is nothing but
Li N ( 1 4 ) ,
where Li s ( z ) = k = 1 z k k s , the Polylogarithm function.

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