Show that y = 2/3e^x + e^(-2x) is a solution of the differential equation y’ + 2y = 2e^x

Zaiden Soto

Zaiden Soto

Open question

2022-08-20

Show that y=23ex+e2x is a solution of the differential equation y+2y=2ex

Answer & Explanation

Karsyn Lam

Karsyn Lam

Beginner2022-08-21Added 7 answers

Step 1
y=23ex+e2x
Differentiate with respect to x
y=23ex2e2x
Step 2
We have to verify the following differential equation:
y+2y=2ex
Substitute the expressions for y' and y, To get
[23ex2e2x]+2[23ex+e2x]=2ex
[23ex2e2x]+[43ex+2e2x]=2ex
23ex2e2x+43ex+2e2x=2ex
(23+43)ex=2ex
Hence verified
Result:
Hint: y=23ex2e2x

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