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Applications of integrals
Beginner2022-01-08Added 36 answers
Beginner2022-01-09Added 34 answers
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Step 1Apply u-substitutionLet u=sec3(x)⇒dx=13sec3(x)tan(x)Thus,∫tan(x)sec3(x)dx=13∫1du=13u+C=sec3(x)3+CResult:sec3(x)3+C
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