Find the integral, full solution \int (2x+3)^{2}dx

Monique Slaughter

Monique Slaughter

Answered question

2022-01-04

Find the integral, full solution
(2x+3)2dx

Answer & Explanation

Mary Herrera

Mary Herrera

Beginner2022-01-05Added 37 answers

Step 1
Given integral,
(2x+3)2dx
Step 2
(2x+3)2dx=(4x2+12x+9)dx
=4x2dx+12xdx+9dx
=4x2dx+12xdx+9dx
=4x33+12x22+9x+C Since xndx=xn+1n+1+C,   n1
=4x33+6x2+9x+C
Raymond Foley

Raymond Foley

Beginner2022-01-06Added 39 answers

Calculate:
(2x+3)2dx
=12u2du
u2du
=u33
12u2du
=u36
=(2x+3)36
=(2x+3)36+C
Lets
karton

karton

Expert2022-01-11Added 613 answers

(2x+3)2dx4x2+12x+9dx4x2dx+12xdx+9dx4x33+6x2+9xAdd CAnswer:4x33+6x2+9x+C

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