Find the integral, full solution ∫(2x+3)2dx

Monique Slaughter

Monique Slaughter

Answered

2022-01-04

Find the integral, full solution
(2x+3)2dx

Answer & Explanation

Mary Herrera

Mary Herrera

Expert

2022-01-05Added 37 answers

Step 1
Given integral,
(2x+3)2dx
Step 2
(2x+3)2dx=(4x2+12x+9)dx
=4x2dx+12xdx+9dx
=4x2dx+12xdx+9dx
=4x33+12x22+9x+C Since xndx=xn+1n+1+C,   n1
=4x33+6x2+9x+C
Raymond Foley

Raymond Foley

Expert

2022-01-06Added 39 answers

Calculate:
(2x+3)2dx
=12u2du
u2du
=u33
12u2du
=u36
=(2x+3)36
=(2x+3)36+C
Lets
karton

karton

Expert

2022-01-11Added 439 answers

(2x+3)2dx4x2+12x+9dx4x2dx+12xdx+9dx4x33+6x2+9xAdd CAnswer:4x33+6x2+9x+C

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?