Let f be a twice differentiable function such that g'(x)=−f(x) and f'(x)=g(x), h(x)=(f(x))^2+(g(x))^2. If h(5)=11, then h(10) is equal to A. 22 B. 11 C. 0 D. 20

Jadiel Bowers

Jadiel Bowers

Answered question

2023-02-25

Let f be a twice differentiable function such that g'x=-fx and f'x=gx, hx=fx2+gx2. If h5=11, then h10 is equal to
A. 22
B. 11
C. 0
D. 20

Answer & Explanation

Gabriel Valencia

Gabriel Valencia

Beginner2023-02-26Added 5 answers

Identify the value of h10.
Consider the given equation as: hx=fx2+gx2
Then, h'x=2fx.f'x+2gx.g'x......(1)
From the given data
gx=f'xg'x=f''xf''x=-fx
Replace the aforementioned values in the equation.(1)
h'x=2fx.f'x-2gx.fxh'x=2fx.gx-2gx.fxh'x=0
Since, hx has some constant value.
Then, the value of h10 is given as:
h10=h5=11h10=11
Therefore, The correct answer is Option B

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