Kamenemoj3q

2023-02-18

What are the absolute extrema of $f\left(x\right)={x}^{3}-3x+1\in \left[0,3\right]$?

Alfonso Marsh

The right option is A $y=\mathrm{tan}\left(x+3\right)$
We know, $\frac{dy}{dx}=1+{y}^{2}$...(i)
$⇒\frac{dy}{1+{y}^{2}}=dx$
$⇒{\mathrm{tan}}^{-1}\left(y\right)=x+c$
$⇒\mathrm{tan}\left(x+c\right)$, where c is arbitrary constant

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