Find the equation of the line perpendicular to y=2x/15 that passes through (−4,4)

Moncelliqo4

Moncelliqo4

Answered question

2022-11-26

Find the equation of the line perpendicular to y = 2 15 x that passes through (−4,4)

Answer & Explanation

Kozuh5F7

Kozuh5F7

Beginner2022-11-27Added 9 answers

Slope of the line, y = 2 15 x ; [ y = m x + c ]
is m 1 = 2 15 [Compared with slope-intercept form of equation]
The product of slopes of the pependicular lines is m 1 m 2 = - 1
m 2 = - 15 2 . The equation of line passing through
( x 1 , y 1 ) having slope of m2 is y - y 1 = m 2 ( x - x 1 )
The equation of line passing through (−4,4) having slope of
- 15 2 is y - 4 = - 15 2 ( x + 4 ) or y = - 15 2 x + 4 - 30 or
y = - 15 2 x - 26
Equation of the line is y = - 15 2 x - 26

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