A cars velocity starting from rest is given by v=(100t)/(2t+15) where v is measured in feet per second. Find the acceleration at the folowing times. a. 5 seconds b. 10 seconds

trokusr

trokusr

Answered question

2022-08-05

A cars velocity starting from rest is given by v = 100 t 2 t + 15 where v is measured in feet per second. Find the acceleration at the folowing times.
a. 5 seconds
b. 10 seconds

Answer & Explanation

Erika Brady

Erika Brady

Beginner2022-08-06Added 19 answers

To find the acceleration take the derivative of the velocity equation:
a ( t ) = 1500 / ( 2 t + 15 ) 2
a.) 1500 / ( 2 ( 5 ) + 15 ) 2 = 2.4
b.) 1500 / ( 2 ( 10 ) + 15 ) 2 = 1.22
vrteclh

vrteclh

Beginner2022-08-07Added 5 answers

Acceleration = dv/dt
= d / d t ( 100 t / ( 2 t + 15 ) ) = ( 100 ( 2 t + 15 ) 2 100 t ) / ( 2 t + 15 ) 2
= 1500 / ( 2 t + 15 ) 2
at 5 secs: a = 1500 / ( 2 5 + 15 ) 2 = 1500 / 625 = 2.4 f t / s 2
at 10 secs: a = 1500 / ( 2 10 + 15 ) 2 = 1500 / 1225 = 1.22 f t / s 2

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