mistergoneo7

2022-07-09

Antiderivative of $\frac{4}{\sqrt{u}}$

Jasper Parsons

Expert

Explanation:
Rewrite $\sqrt{u}$ as ${u}^{1/2}$. Thus, $\frac{4}{\sqrt{u}}=4{u}^{-1/2}$.
Recall that for all $n\ne -1$.
Then,

auto23652im

Expert

Explanation:
You can re-write this as $4{u}^{-\frac{1}{2}}$. Now, use the rule for integrating functions of the form $\int {u}^{n}du$

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