myntfalskj4

2022-07-09

How to find instantaneous rate of change for $y=f\left(t\right)=-16\left({t}^{2}\right)+59t+39$ when t=1?

Johnathan Morse

Expert

The instantaneous rate of change of y=f(t) when t=1 is given by f'(1)
We have
$f\left(t\right)=-16{t}^{2}+59t+39$
Differentiating wrt t we get
f'(t)=-32t+59
So when t=1 we have:
f'(1)=-32+59=27
Hence, the instantaneous rate of change of y=f(t) when t=1 is 27

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