On what integration domain is the author finding the anti derivative? Find the antiderivative(s):

juanberrio8a

juanberrio8a

Answered question

2022-06-08

On what integration domain is the author finding the anti derivative?
Find the antiderivative(s): 1 x 2 a 2 d x.
1 x 2 a 2 d x
1 ( x + a ) ( x a ) d x
1 2 a ( 1 x a 1 x + a ) d x
1 2 a [ ln ( x a ) ln ( x + a ) ] + C
1 2 a ln ( | x a x + a | ) + C , x ± a
1 x 2 a 2 is a discontinuous function, and there are three integration domains of it: ( , a ), ( a , a ) and ( a , + ). We will get three different family of functions as antiderivatives for the three different integration domains of this function, and two antiderivatives belonging to two different integration domains/family of functions will not differ by a constant.
My question is that my book found out the antiderivative belonging to which integration domain?

Answer & Explanation

Misael Li

Misael Li

Beginner2022-06-09Added 14 answers

Step 1
If the component pieces of a function are governed by the same 'rule' that has a primitive (e.g., this is not so in the case of f ( x ) = | 1 x | ) ,, then, from the Fundamental Theorem of Calculus, we do expect their primitives to differ by a constant.
(It is accurate to say that on each integration interval, 1 x has primitive ln | x | . )
Step 2
In the given solution, there has been no additional condition imposed on the integrand (to apply a certain law/theorem, for example) on top of the starting restriction x ± a ,, so there's no basis for inferring that the result doesn't apply on ( , a ) or ( a , a ) or ( a , ) .
Armeninilu

Armeninilu

Beginner2022-06-10Added 4 answers

Step 1
Your book used the absolute value in logarithm and this makes the antiderivative having a unique expression. It gives the same formula for the three domains.
If your integrand was f ( x ) = 1 | x 2 1 |
Step 2
You won't get the same expression. in each of the intervalls ( , 1 ) ( 1 , 1 ) , ( 1 , ), there is a special antiderivative.

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