If y=\frac{1}{1+x^{2}}, what are the points of inflection of the

broggesy9

broggesy9

Answered question

2022-04-24

If y=11+x2, what are the points of inflection of the graph f (x)?

Answer & Explanation

belamontern9i

belamontern9i

Beginner2022-04-25Added 19 answers

Step 1
The inflection points are the zeroes of the second derivative. So, first of all, we need to compute it:
f(x)=11+x2
f(x)=1(1+x2)22x=2x(1+x2)2
fx)=2(1+x2)22x(2(1+x2)2x)(1+x2)4
-2(1+x2)2-8x2(1+x2)(1+x2)43
6x22(1+x2)3
Step 2
So, we need to find the zeroes of this function, which are the zeroes of its numerator:
6x22=03x21=0x2=13x=±13

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?