What is the equation of the normal line



Answered question


What is the equation of the normal line of f(x)=5x32x23x1 at x=-8?

Answer & Explanation



Beginner2022-04-09Added 15 answers

At x=8,f(x)=5(8)32(8)23(8)1
Hence we are see normal at (-8, -2665)
Slope of tangent is given by f'(-8) and as f(x)=15x24x3
slope of tangent is 15(8)24(8)3=989
and hence slope of normal is 1989 and
equation of normal is y+2665=1989(x+8)
or x+989y+2635693=0

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