What is the equation of the line tangent

Abbey Ellison

Abbey Ellison

Answered question

2022-04-08

What is the equation of the line tangent to f(x)=3x4x22x at x=1?

Answer & Explanation

bondsk384r

bondsk384r

Beginner2022-04-09Added 12 answers

Explanation:
The equation of the tangent in point-slope form is.
yy1=m(xx1)
where m represents the slope and (x1,y1) a point on the line
Reminder mtannt=f(x) at x=a
f(x)=12x32x2
f(1)=1222=16=mtannt
and f(1)=-3-1-2=-6
Using m=-16 and (x1,y1)=(1,6)
y+6=16(x1)
y=16x+166
y=16x+10 is the equation of tangent

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