What is the equation of the line normal

Tyson Mcneil

Tyson Mcneil

Answered question

2022-04-07

What is the equation of the line normal to f(x)=x36x22 at x=1?

Answer & Explanation

Buizzae77t

Buizzae77t

Beginner2022-04-08Added 13 answers

Find the slope of the tangent line, to which the normal line is perpendicular.
f(1)=-7
The line will pass through the point (1, -7)
f(x)=3x212x
f'(1)=-9
If the slope of the tangent line is -9, the slope of the normal line will be the opposite reciprocal of -9 since the lines are perpendicular. This means the slope is 19.
Write the equation in point-slope form:
y+7=19(x1)

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