Finding the limit of a sequence \(\displaystyle\lim_{{{n}\to\infty}}{\sqrt[{{3}}]{{{n}^{{2}}}}}{\left({\sqrt[{{3}}]{{{n}+{1}}}}-{\sqrt[{{3}}]{{{n}}}}\right)}\)

Henry Winters

Henry Winters

Answered question

2022-04-07

Finding the limit of a sequence
limnn23(n+13n3)

Answer & Explanation

regulerenes4w

regulerenes4w

Beginner2022-04-08Added 10 answers

limnn23(n+13n3)((n+1)23+n(n+1)3+n23)((n+1)23+n(n+1)3+n23)
=limn(n23·(n+1-n))÷n23((n+1)23+n(n+1)3+n23)÷n23=13

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