How do you write an equation of the line tangent to x2+y2=169 at the point...
How do you write an equation of the line tangent to at the point (5,12)?
Answer & Explanation
Beginner2022-02-16Added 9 answers
Here we have the equation of a circle:
To determine the slope of a tangent to the circle at any point we need to use implicit differentiation.
At the point (5,12),
So the tangent has a slope of and passes through the point (5,12)
The equation of a line of slope m, passing through the point is:
The tangent would therefore have the equation:
Beginner2022-02-17Added 10 answers
Explanation: Differentiate implicitly: So, for x=5, y=12: The equation of the tangent line is: 12y+5x=169
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