interestilo6z9

2022-02-16

For $f\left(x\right)={\left(5+4x\right)}^{2}$, what is the equation of the line tangent to x=7?

Elodie Williamson

First find the slope at x=7, then use the point slope format to find the tangent line.
f(x)'=8(5+4x)
f'(7)=264
f(7)=1089
$\left(y-{y}_{1}\right)=m\left(x-{x}_{1}\right)$
(y-1089)=264(x-7)
Tangent Line : y=264x-759

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