For f(x)=(5+4x)2, what is the equation of the line tangent to x=7?
interestilo6z9
Answered question
2022-02-16
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Answer & Explanation
Elodie Williamson
Beginner2022-02-17Added 7 answers
First find the slope at x=7, then use the point slope format to find the tangent line.
f(x)'=8(5+4x)
f'(7)=264
f(7)=1089
(y-1089)=264(x-7)
Tangent Line : y=264x-759
f(x)'=8(5+4x)
f'(7)=264
f(7)=1089
(y-1089)=264(x-7)
Tangent Line : y=264x-759
