Leroy Little

2022-02-12

How do you find the equation of the line tangent to the graph of $y={x}^{2}-3$ at the point P(2,1)?

Addison Matthews

Beginner2022-02-13Added 13 answers

Explanation:

The slope of a tangent to

At (x,y)=(2,1) the slope becomes (substituting 2 for x) m=4

The general slope point form for a line with slope m through a point

Substituting m=4,

y-1=4(x-2)

This could be re-written in standard form as

4x-y=7