What is the equation of the line tangent to f(x)=\frac{\sin

Bryant Miranda

Bryant Miranda

Answered question

2022-02-12

What is the equation of the line tangent to f(x)=sinπx at x=1?

Answer & Explanation

ljmolerovae

ljmolerovae

Beginner2022-02-13Added 15 answers

sinπ=0, so, for all x0, we have f(x)=0.
Therefore, f'(1)=0. (By definition or by properties/rules for differentiation.)
At the point where x=1, we get y=f(1)=0,
and the equation of the line with slope m=0 through (1,0) is y=0
golfachukc8

golfachukc8

Beginner2022-02-14Added 13 answers

For f(x)=sin(πx), we get f(1)=sinπ=0
and
f(x)=cos(πx)[ddx(πx)]=cos(πx)[ddx(πx1)]
=cos(πx)[πx2]=πx2cos(πx)
So, f(1)=πcosπ=π
The line through (1,0) with slope m=π is
y=πxπ

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