How do you find the equation of the line tangent

dannyhaden6gjj

dannyhaden6gjj

Answered question

2022-02-13

How do you find the equation of the line tangent to the graph of y=x22x at the point (-2,8)?

Answer & Explanation

uporabah5pn

uporabah5pn

Beginner2022-02-14Added 11 answers

Explanation:
Take the derivative of the given function
dydx=2x2
Find dydx for given value of x
dydx=2(2)2=42=6
Now create the point slope form of a line and the solve for y
y-8=-6(x-(-2))
y-8=-6(x+2)
y-8=-6x-12
y=-6x-4
krugom1if

krugom1if

Beginner2022-02-15Added 6 answers

Explanation:
y=x22x
dydx=2x2
The general equation for the tangent is given by:
y=mx+c
m=2x-2
Since x=-2 then:
m=(2×2)2=6
Since y=8:
8=(6×2)+C
C=-4
So the equation of the tangent becomes:
y=-6x-4

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