Jason Farmer

Answered question

2021-01-16

Find the limits: As $x\to \mathrm{\infty },\frac{-2x\left({x}^{2}+4\right)}{-7-7{x}^{4}}$

Answer & Explanation

Lacey-May Snyder

Skilled2021-01-17Added 88 answers

The given function is $\frac{-2x\left({x}^{2}+4\right)}{\left(-7-7{x}^{4}}$
Evaluate the limits at the endpoints as shown below.
$\underset{x\to \mathrm{\infty }}{lim}\frac{-2x\left({x}^{2}+4\right)}{-7-7{x}^{4}}$
$=\underset{x->\mathrm{\infty }}{lim}\frac{{x}^{3}\left(-2-\frac{8}{{x}^{2}}\right)}{{x}^{4}\left(\frac{-7}{{x}^{4}}-7\right)}$
$=\underset{x->oo}{lim}\frac{{x}^{3}\left(-2-\frac{8}{{x}^{2}}\right)}{{x}^{4}\left(\frac{-7}{{x}^{4}}-7\right)}$
$=\underset{x\to \mathrm{\infty }}{lim}\frac{\left(-2-\frac{8}{{x}^{2}}\right)}{\left(x\left(\frac{-7}{{x}^{4}}-7\right)}=0$

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?