What is the antiderivative of ln(x)^2?

Braden Miranda

Braden Miranda

Answered question

2023-02-17

What is the antiderivative of ln ( x ) 2 ?

Answer & Explanation

Shiloh Hinton

Shiloh Hinton

Beginner2023-02-18Added 9 answers

Here,
I = ln ( x ) 2 d x
Using Power-coefficient Rule :
ln x n = n ln x , we get
I = ln x 2 d x = 2 ln x ... ( A )
Using , Integration by parts:
( u v ) d x = u v d x - ( u v d x ) d x
u = ln x and v = 2 u = 1 x and v d x = 2 x
I = ln x 2 x - 1 x 2 x d x + c
I = 2 x ln x - 2 d x + c
I = 2 x ln x - 2 x + c
I = 2 x [ ln x - 1 ] + c
...........................................................................................................
Note:
If I = ( ln x ) 2 ,then
I = ( ln x ) 2 1 d x
Using , Integration by parts:
u = ( ln x ) 2 and v = 1 u = 2 ln x x and v d x = x
I = ( ln x ) 2 1 d x - 2 ln x x x d x
= ( ln x ) 2 x - 2 ln x
Using the aforementioned outcome for ( A )
I = x ( ln x ) 2 - { 2 x [ ln x - 1 ] } + c
Xander Torres

Xander Torres

Beginner2023-02-19Added 1 answers

A function's antiderivative is essentially the integral of the function. So we get:
ln ( x ) 2   d x
I'm assuming that we have ln x 2   d x .
Using logarithm rules, we get:
= 2 ln x   d x
= 2 ln x   d x
This is a common integral, where ln x   d x = x ln x - x + C .
= 2 x ln x - 2 x + C

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