What is the series limit for the Balmer series? (The series limit, like the name suggests, is the last line of the given series - the smallest wavelength that's still part of the same set of spectral lines) A. 364.6nm B. 121.6nm C.656.3nm D. 385.4nm

gibbokf5

gibbokf5

Answered question

2023-01-01

What is the series limit for the Balmer series? (The series limit, like the name suggests, is the last line of the given series - the smallest wavelength that's still part of the same set of spectral lines)
A. 364.6nm
B. 121.6nm
C.656.3nm
D. 385.4nm

Answer & Explanation

Keely Franco

Keely Franco

Beginner2023-01-02Added 11 answers

Rydberg is our knight in shining armour, again! We know, for the Balmer series n 1 = 2. The series limit, or the very last line in the series, will be obtained by putting n 2 = . Thus the Balmer series limit can be found as –
1 λ = R ( 1 2 2 1 2 ) = R 4 m 1
}\Rightarrow \lambda_\infty=\frac4Rm=3.646\times10^{−7}m=364.6nm.Show External URL Show Embeded Code Hide MathML Code⇒λ∞=4Rm=3.646×10−7m=364.6nm. λ = 4 R m = 3.646 × 10 7 m = 364.6 n m .
Option (a) is correct!

The significance of the wavelength is, it’s the Balmer line with the smallest wavelength. The next line with a smaller wavelength will be the first line of the Lyman series, which is 121.6 nm. This essentially means, there will be no spectral lines in the range 121.6 nm - 364.6nm.

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