Evaluate the definite integral. int_0^5 8(t^5-t^3+1)dt

psetancabyc

psetancabyc

Answered question

2022-12-17

Evaluate the definite integral.
0 5 8 ( t 5 t 3 + 1 ) d t

Answer & Explanation

Darion Newman

Darion Newman

Beginner2022-12-18Added 3 answers

Solution:
0 5 8 ( t 5 t 3 + 1 ) d t = 8 [ 0 5 t 5 d t 0 5 t 2 d t + 0 5 1 d t ] = 8 [ t 6 6 | 0 5 t 8 4 0 5 + t 0 5 ] = 8 [ 15625 6 625 4 + 5 ] = 2 3 [ 29435 ] = 19623.23

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