Proof that a^{\frac{1}{m}}<a^{\frac{1}{n}} with m<n,0<a<1 and n,m\in\mathbb{N}

veksetz

veksetz

Answered question

2022-01-13

Proof that a1m<a1n with m<n,0<a<1 and n,mN

Answer & Explanation

Pademagk71

Pademagk71

Beginner2022-01-14Added 34 answers

Step 1
Rise both side of the inequality to the power
m×n
to find
an<am
that is true since so since
n>m
an=am×anm<am
because anm<1
sirpsta3u

sirpsta3u

Beginner2022-01-15Added 42 answers

Step 1
Set
b=a1m
and
B=a1n,
where
0<a<1,
and
n>m
By definition:
bm=Bn=a<1
This implies
0<b, B<1
Bn=BmBnm=bm
Since Bnm<1 it follows that Bm>bm, or (Bb)m>1, which implies Bb>1

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