Why \lim_{n \rightarrow \infty} \frac{(2^{2})^{\sqrt{n}}}{(1+(10)^{-2^{2}})^{n}}

Victor Wall

Victor Wall

Answered question

2022-01-12

Why limn(22)n(1+(10)22)n

Answer & Explanation

Esta Hurtado

Esta Hurtado

Beginner2022-01-13Added 39 answers

Observe that for n big enough we have
5<(1+104)n
So 5n<(1+104)n
and then 4n(1+104)n<4n5n=(45)n0
Thomas Lynn

Thomas Lynn

Beginner2022-01-14Added 28 answers

Why do you come to that conclusion? You are looking at
4n(1+104)n
Now notice that 4>1 and 1+104>1, so both denominator and numerator are growing, but as n grows much slower than n the numerator will also grow slower than the denominator, so the whole thing goes to 0.
To see this simply apply a logarithm (to get rid of the different bases):
log=log(4)nlog(1+104)n
Obviously this goes to  as n.

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