To find, wether '1' lies in the range of f, where f(x)=[ln((7x-x^2)/(12))]^(3/2)? For the given function, the question is whether, f(x) can equal 1 for some real value of x?

MMDCCC50m

MMDCCC50m

Answered question

2022-11-20

To find, wether '1' lies in the range of f, where f ( x ) = [ l n ( 7 x x 2 12 ) ] 3 2 ?
For the given function, the question is whether, f(x) can equal 1 for some real value of x?

Answer & Explanation

Gilbert Petty

Gilbert Petty

Beginner2022-11-21Added 23 answers

The tactic is to make things simpler.
If there is x such that f ( x ) = [ l n ( 7 x x 2 12 ) ] 3 2 = 1 then we have also
l n ( 7 x x 2 12 ) = 1, that is, 7 x x 2 12 = e or even simpler
x 2 7 x + 12 e = 0
You just have to check wether this equation has real solutions.

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