Modeling drunkeness over time. So you have the function of drunkenness,D(t), the amount of alcohol in your blood, for t>0, over time,t in hours: D(t)=T-ct.

reevelingw97

reevelingw97

Answered question

2022-11-17

Modeling drunkeness over time
So you have the function of drunkenness,D(t), the amount of alcohol in your blood, for t > 0, over time,t in hours:
D ( t ) = T c t
c being the arbitrary amount of alcohol your liver will process in 1 hour. T being the total amount of alcohol you have drunk at time t.
So T does depend on t, but it still a totally arbitrary amount.
As a piece wise function based on T = c n t. c n = n c with n being some non negative number, representing the number of drinks of strength c had in 1 hours time:
T = { t = 1 n 1 c t = 2 n 2 c . . . t = n n n c
So to find T for a certain time, t,
T ( t = n ) = n 1 c + n 2 c . . . + . . . n n c = ( n 1 + n 2 + n n ) c
The number of drinks had each hour is totally arbitrary. Now what I want to do is to compare this between different values of c. Like comparing the same amount of drinking between a light beer (call it 1c) and a craft beer (2c). Is there a way to generalize this.
For example:
T = { t = 1 2 c t = 2 1 c t = 3 3 c
T ( t = 3 ) = 6 c
So
D ( t = 3 ) = 3 c
but if c = 2 c
T ( t = 3 ) = 12 c
and
D ( t = 3 ) = 9 c
So drunkenness is not a linear relationship related to the strength of alcohol you are drinking.

Answer & Explanation

andytronicoh4t

andytronicoh4t

Beginner2022-11-18Added 18 answers

B - Big mac Burger
W - whopeers
Given, two Bif mac and three whoppers contain 520 mgs of cholesterol
2 B + 3 w = 520
3 Big Mcs and one whopper contain 353 m contain 353 mgs ofcholesterol
3 B + 1 w = 353 7 B = 539 B = 539 7 = 77 2 × 77 + 3 w = 520 154 + 3 w = 520 3 w = 520 154 3 w = 360 w = 122  mgs
1 Big Mac contains 77 mgs of cholesterol
1 whopper contains 122 mgs of cholesterol

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