Arithmetic progression and polynomials. Suppose the quadratic polynomial p(x)=ax^2+bx+c has positive coefficients a,b,c such that these are in AP in the given order.

Filloltarninsv9p

Filloltarninsv9p

Answered question

2022-11-11

Arithmetic progression and polynomials
Suppose the quadratic polynomial
p ( x ) = a x 2 + b x + c
has positive coefficients a,b,c such that these are in AP in the given order. If m and n are the integer zeros of the polynomial then what is the value of m + n + m n? I have tried quadratic formula but ain't getting the answer.

Answer & Explanation

Quinten Cervantes

Quinten Cervantes

Beginner2022-11-12Added 13 answers

Step 1
Since m and n are roots of the polynomial we have
a x 2 + b x + c = a ( x m ) ( x n ) = a x 2 a ( m + n ) x + a m n
Then,
m + n = b a and m n = c a
So, since a,b and c are in AP we get
m + n + m n = b a + c a = c b a = b + b a b a = b a a = b a 1
and b a = ( m + n ), then
m + n + m n = ( m + n ) 1 m n + 2 ( m + n ) + 4 = 3
Step 2
So ( m + 2 ) ( n + 2 ) = 3
Now, since 3 is a prime we have ( m , n ) { ( 1 , 1 ) , ( 1 , 1 ) , ( 3 , 5 ) , ( 5 , 3 ) } . Notice that ( m , n ) = ( 1 , 1 ) or ( m , n ) = ( 1 , 1 ) implies b = 0, but we know that a,b and c are positive. So, ( m , n ) = ( 3 , 5 ) or ( 5 , 3 ), and then
m + n + m n = 8 + 15 = 7

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