Evaluate log ⁡ 64 using the change of base formula?Is that even possible? I mean,...

Usually, $\log$ means ${\log }_e=\ln$ or ${\log }_{10}$. Either way, there isn't a neat answer to the question. The most you can do is write $\ln 64=6\ln 2$ and ${\log }_{10}64=6{\log }_{10}2$, using that $2^6=64$. Now the problem boils down to knowing the values of $\ln 2$ and ${\log }_{10}2$. These values can be approximated numerically using calculus, for example.