How do you graph f(x)=(2x−1)/(x+3) using holes, vertical and horizontal asymptotes, x and y intercepts?

priscillianaw1

priscillianaw1

Answered question

2022-09-29

How do you graph f ( x ) = 2 x - 1 x + 3 using holes, vertical and horizontal asymptotes, x and y intercepts?

Answer & Explanation

sodoendev7

sodoendev7

Beginner2022-09-30Added 7 answers

f ( x ) = 2 x - 1 x + 3
f ( x ) = 2 ( x + 3 ) - 7 x + 3
f ( x ) = 2 - 7 x + 3

Therefore, the horizontal asymptote is y=2 and the vertical asymptote is x=−3 What asymptotes mean is that the end points of your lines are APPROACHING y=2 and x=−3

Now, to find the intercepts
When y=0, x = 1 2
When x=0, y = - 1 3

After plotting the intercepts and the asymptotes, you should get something like this
graph{(2x-1)/(x+3) [-10, 10, -5, 5]}

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