How do you graph f(x)=−1/(x−2) using holes, vertical and horizontal asymptotes, x and y intercepts?

Jazmyn Pugh

Jazmyn Pugh

Answered question

2022-09-23

How do you graph f ( x ) = - 1 x - 2 using holes, vertical and horizontal asymptotes, x and y intercepts?

Answer & Explanation

Jonah Cooke

Jonah Cooke

Beginner2022-09-24Added 7 answers

Analytically:

Setting the numerator = 0 gives x-intercepts. There are no factors in the numerator, so there are no x-intercepts.

Setting the denominator =0 yields vertical asymptotes:
x−2=0 yields a vertical asymptote at x=2

Horizontal asymptotes are found based on the degree of the numerator and denominator. If the degree of the numerator is one less than the degree of the denominator, the horizontal asymptote is the x-axis (y=0)

Since there is no variable in the numerator, the degree = 0.
The degree of the denominator is 1.

From the graph:
graph{-1/(x-2) [-10, 10, -5, 5]}

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?