Javion Henry

Answered

2022-07-27

Solve the equation.

${T}_{2}=$

${T}_{1}=300K,k={\mathrm{1.38066.10}}^{-23}$

${T}_{1}^{2}{e}^{\frac{-0.8eV}{k\ast {T}_{1}}}={T}_{2}^{2}\ast {e}^{\frac{-0.4eV}{k\ast {T}_{2}}}$

${T}_{2}=$

${T}_{1}=300K,k={\mathrm{1.38066.10}}^{-23}$

${T}_{1}^{2}{e}^{\frac{-0.8eV}{k\ast {T}_{1}}}={T}_{2}^{2}\ast {e}^{\frac{-0.4eV}{k\ast {T}_{2}}}$

Answer & Explanation

Rihanna Robles

Expert

2022-07-28Added 18 answers

The LHS of this eqn consists of all known constants, so youcan evaluate it and get a constant ${C}_{1}$ .

The RHS can be written in the form ${x}^{2}\mathrm{exp}({C}_{2}/x)$ , where x is the temp ${T}_{2}$ and ${C}_{2}=-0.4/k$

Form the eqn ${C}_{1}-{x}^{2}\mathrm{exp}({C}_{2}/x)=0$ and put it intothe "solver" mode on a TI-83 plus or TI-84 plus to solve forx.

The RHS can be written in the form ${x}^{2}\mathrm{exp}({C}_{2}/x)$ , where x is the temp ${T}_{2}$ and ${C}_{2}=-0.4/k$

Form the eqn ${C}_{1}-{x}^{2}\mathrm{exp}({C}_{2}/x)=0$ and put it intothe "solver" mode on a TI-83 plus or TI-84 plus to solve forx.

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