Pierre Holmes

Answered

2022-07-22

A normal human body temperature can range from ${33.2}^{\circ}C$ to ${38.2}^{\circ}C$. This range includes variations with gender, time of day, and where the measurement is taken. Part A What is this range in ${}^{\circ}F$? Express your answer in degrees Fahrenheit. Enter your answers numerically separated by a comma.

Answer & Explanation

Lillianna Mendoza

Expert

2022-07-23Added 16 answers

To develop this problem it is necessary to use the expression that allows us to convert the degrees Celsius to Fahrenheit. The expression that allows to realize it is given mathematically by:

${}^{\circ}F={(}^{\circ}C\cdot \frac{9}{5})+32$

In this way for ${33.2}^{\xb0}C$

${}^{\xb0}F={(}^{\xb0}C\cdot \frac{9}{5})+32{\phantom{\rule{0ex}{0ex}}}^{\xb0}F=(32.2\cdot \frac{9}{5})+32{\phantom{\rule{0ex}{0ex}}}^{\xb0}F=91.76$

In this way for 38.2C

${}^{\xb0}F={(}^{\xb0}C\cdot \frac{9}{5})+32{\phantom{\rule{0ex}{0ex}}}^{\xb0}F=(38.2\cdot \frac{9}{5})+32{\phantom{\rule{0ex}{0ex}}}^{\xb0}F=100.76$

Expressed in a range term, we can say that the measure in degrees Fahrenheit is: $[{91.76}^{\xb0}F,{100.76}^{\xb0}F]$

${}^{\circ}F={(}^{\circ}C\cdot \frac{9}{5})+32$

In this way for ${33.2}^{\xb0}C$

${}^{\xb0}F={(}^{\xb0}C\cdot \frac{9}{5})+32{\phantom{\rule{0ex}{0ex}}}^{\xb0}F=(32.2\cdot \frac{9}{5})+32{\phantom{\rule{0ex}{0ex}}}^{\xb0}F=91.76$

In this way for 38.2C

${}^{\xb0}F={(}^{\xb0}C\cdot \frac{9}{5})+32{\phantom{\rule{0ex}{0ex}}}^{\xb0}F=(38.2\cdot \frac{9}{5})+32{\phantom{\rule{0ex}{0ex}}}^{\xb0}F=100.76$

Expressed in a range term, we can say that the measure in degrees Fahrenheit is: $[{91.76}^{\xb0}F,{100.76}^{\xb0}F]$

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