Ellie Benjamin

2022-07-10

Get d from Free space path loss equation
How would I get $d$ from this: $L=10n{\mathrm{log}}_{10}\left(d\right)+C$
I've got this so far:
$\begin{array}{rl}L-C& =10n{\mathrm{log}}_{10}\left(d\right)\\ \frac{L-C}{10n}& ={\mathrm{log}}_{10}\left(d\right)\end{array}$
Is it: ${2}^{10}\cdot \frac{L-C}{10n}=d$???

Jamarcus Shields

Expert

Exponentiate both sides:
$\frac{L-C}{10n}={\mathrm{log}}_{10}\left(d\right)⇔{10}^{\frac{L-C}{10n}}={10}^{{\mathrm{log}}_{10}\left(d\right)}=d$

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