Let be a field with characteristic and the field of rational functions in 2 variables over . We consider the subfield .
Show that .
We need the property that , which we showed already. But I actually do not know how to use it here. I can not work well with that field in 2 variables..
Beginner2022-06-30Added 13 answers
Keep in mind that in some fields so that You are in possession of the extension's degree is calculated as the product of the extensions' degrees. and .
Use this for example with , applying the outcome you are aware of twice.
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