Suppose thatZSKG(x)=\log_3(2x+1)-2ZSK. (a) What is the domain of G? (b)

jermandcryspza3

jermandcryspza3

Answered question

2022-04-02

Suppose that G(x)=log3(2x+1)-2.
(a) What is the domain of G?
(b) What is G(40)? What point is on the graph of G?
(c) If G(x)=3, what is x? What point is on the graph of G?
(d) What is the zero of G?

Answer & Explanation

Drahthaare89c

Drahthaare89c

Beginner2022-04-03Added 19 answers

Hello. Since your question has multiple sub-parts, we will solve first three sub-parts for you. If you want remaining sub-parts to be solved, then please resubmit the whole question and specify those sub-parts you want us to solve.
Given that:
G(x)=log3(2x+1)2
To calculate the domain of “G” then,
G(x) is logarithms function,
So the domain of logarithms function is defined,
2x+1>0
2x1
x12
x(12,)
(b)
To calculate G (40)
Substitute x=40 in given equation then,
G(40)=log3(2(40)+1)2
=log3(81)2
=log3(3)42
4log3(3)2
=412
=2
Hence the value of G (40) is 2
arrebusnaavbz

arrebusnaavbz

Beginner2022-04-04Added 18 answers

To calculate the points on the graph,
G(x)=0
log3(2x+1)2=0
log3(2x+1)=2
2x+1=32
2x+1=9
2x=8
x=4
Hence   the   pts   of  the   graph   is   (4,0)   and 
(0, -2).
(c)
To calculate the value of x when G(x)=3 then,
3=log3(2x+1)2
log3(2x+1)=3+2
log3(2x+1)=5
2x+1=35
2x+1=243
2x=242
x=121
The value of x=121 when G(x)=3

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?