afadimoz4

2022-03-16

A triangular frame measures $3\sqrt{2}$ m on two sides and $4\sqrt{2}$ m on the base. What is the perimeter?

danomangli

Beginner2022-03-17Added 3 answers

The formula for perimeter calculation of a triangle is $a+b+c$

where a, b, and c are the three sides of the triangle.

So in this case, if we consider

$a=b=3\sqrt{2}m$

and$c=4\sqrt{2}m$

Hence as per the formula

Perimeter$P=a+b+c$

$=3\sqrt{2}m+3\sqrt{2}m+4\sqrt{2}m$

Taking$\sqrt{2}$ as a common term out,

$=\sqrt{2}(3+3+4)m$

$=10\sqrt{2}m$

where a, b, and c are the three sides of the triangle.

So in this case, if we consider

and

Hence as per the formula

Perimeter

Taking

Misurina6am

Beginner2022-03-18Added 3 answers

Perimeter of a triangle= sum of all three side lengths

Here,

Two sides are equal and have value$=3\sqrt{2}m$

Length of the third side$=4\sqrt{2}m$

So, perimeter$=(2\times 3\sqrt{2}+4\sqrt{2})m$

$=(6\sqrt{2}+4\sqrt{2})m$

$=10\sqrt{2}m$ .

Here,

Two sides are equal and have value

Length of the third side

So, perimeter

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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